A steel wire has a length of 300 cm and a cross-sectional area of 0.50 mm2 . The Young modulus of steel is 2.0 x 1011Pa.
One end of the wire is attached to a fixed point. A load of 10 N is hung from the other end. The wire obeys Hooke’s law.
What is the extension of the wire?
A 3.0 x 10-7 m
B 3.0 x 10-5 m
C 3.0 x 10-4 m
D 3.0 x 10-2 m
ANSWER: C
The Physics Behind answer
- One version of Hooke's Law states that stress [F/A] is proportional to strain [x/L], and that the proportionality constant is Young modulus [E] where F is force, A is area, L is original length, and x is the extension which is being asked in this question.
E = (F / A) / (x / L)
E = FL / xA
x = FL / AE
- The extension x therefore is
x = (30 N m) / 100 000 N
x = 0..0003 m
[option C]
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