Answer:
Electric field strength is the force per unit positive charge.
Answer:
Electric field is a vector quantity and that at any distance x, there are two fields - one due to A and one due to B.
These 2 fields are combined to determine the electric field strength E at point P.
Based on the graph,
E is zero at x = 10 cm.
E is positive at x < 10 cm.
E is negative at x > 10 cm.
These are only possible if charges A and B have the same sign.
Answer:
If there is only one charge creating the field, then E and x follow the inverse-square law.
In the situation in this question, the field E is due to a combination of two fields.
Answer:
Electric field strength E is given by
E = kQ / x2 .
Let EA and EB be the field due to charge A and charge B, respectively.
We know from the graph that at x = 10 cm, EA and EB.
EA = EB
kQA / x2 = kQB / (15 - x)2
QA / 102 = QB / 52
QA / QB = 4.0
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