Answer:
- An ideal gas is a gas that obeys the equation pV/T = constant where p is pressure, V is volume, and T is temperature of the gas.
Answer:
An equation linking the macroscopic properties p and V of an ideal gas to its microscopic properties is pV = ⅓ Nm<c2>, where
p and V are pressure and volume, respectively
Nm is the number of atoms times the mass of each atom, thus, the mass of the gas
<c2> is the mean-square speed
Substituting the given values, the <c2> is
<c2> = 3pV/Nm
<c2> = 3 (2.12 x 107) (1.84 x 10-2) / (3.20)
The root-mean-square speed is the square root of <c2>, so the answer is 605 m s-1.
Answer:
The amount n is calculated from the rearranged Ideal Gas equation.
n = pV/RT
The equation gives the n when all quantities are expressed in SI units. This means that the temperature T must be converted to kelvin before plugging in values.
n = (2.12 x 107) (1.84 x 10-2) / (8.31 x 295)
Therefore, n = 159 mol.
Answer:
The 2 versions of Ideal Gas Law i.e. pV = nRT and pV = NkT, when combined gives
nR = Nk
The mass M of a gas is equal to the number of atoms N in the gas multiplied by mass m.
M = Nm
so, N = M / m
Combining the 2 equations above, we should get
nR = M k/ m
m = Mk / nR
We also know that the Boltzmann constant k is the ratio of the gas constant R and Avogagadro’s number NA.
k = R / NA
k / R = 1 / NA
So our working equation becomes
mass of one atom m = M / (nNA)
where M is the mass of the gas and NA is the Avogadro’s constant.
The mass m, therefore is,
m = 3.20 / (159 x 6.02 x 1023)
m = 3.34 x 10-26 kg
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